8^(3-4x)=(2^-9x)

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Solution for 8^(3-4x)=(2^-9x) equation: 



8^(3-4x)=(2^-9x)

We move all terms to the left:

8^(3-4x)-((2^-9x))=0

We add all the numbers together, and all the variables

8^(-4x+3)-((2^-9x))=0



We calculate terms in parentheses: -((2^-9x)), so:

(2^-9x)

We get rid of parentheses

-9x+2^

We add all the numbers together, and all the variables

-9x

Back to the equation:

-(-9x)



We get rid of parentheses

8^(-4x+3)+9x=0

We add all the numbers together, and all the variables

9x+8^(-4x+3)=0

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